Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0010111010001000000111 |
3 | 1111010020122000021120100211 |
4 | 2210320330002322020013 |
5 | 2441122124031402213 |
6 | 40033241052420251 |
7 | 2246434664242105 |
oct | 244707402721007 |
9 | 44106560246324 |
10 | 11331131122183 |
11 | 3679562131064 |
12 | 1330070a77687 |
13 | 6426a0a74402 |
14 | 2b2603042c75 |
15 | 149b36e2453d |
hex | a4e3c0ba207 |
11331131122183 has 2 divisors, whose sum is σ = 11331131122184. Its totient is φ = 11331131122182.
The previous prime is 11331131122067. The next prime is 11331131122247. The reversal of 11331131122183 is 38122113113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331131122183 - 29 = 11331131121671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331131125183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565561091 + 5665565561092.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565561092).
Almost surely, 211331131122183 is an apocalyptic number.
11331131122183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131122183 is an equidigital number, since it uses as much as digits as its factorization.
11331131122183 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 31.
Adding to 11331131122183 its reverse (38122113113311), we get a palindrome (49453244235494).
The spelling of 11331131122183 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred twenty-two thousand, one hundred eighty-three".
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