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11331131122247 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0010111010001001000111
31111010020122000021120110012
42210320330002322021013
52441122124031402442
640033241052420435
72246434664242226
oct244707402721107
944106560246405
1011331131122247
113679562131112
121330070a7771b
136426a0a74451
142b2603042cbd
15149b36e24582
hexa4e3c0ba247

11331131122247 has 2 divisors, whose sum is σ = 11331131122248. Its totient is φ = 11331131122246.

The previous prime is 11331131122183. The next prime is 11331131122249. The reversal of 11331131122247 is 74222113113311.

It is a strong prime.

It is an emirp because it is prime and its reverse (74222113113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331131122247 - 26 = 11331131122183 is a prime.

Together with 11331131122249, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131122249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565561123 + 5665565561124.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565561124).

Almost surely, 211331131122247 is an apocalyptic number.

11331131122247 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131122247 is an equidigital number, since it uses as much as digits as its factorization.

11331131122247 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6048, while the sum is 32.

Adding to 11331131122247 its reverse (74222113113311), we get a palindrome (85553244235558).

The spelling of 11331131122247 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, one hundred twenty-two thousand, two hundred forty-seven".