113311312031 has 2 divisors, whose sum is σ = 113311312032. Its totient is φ = 113311312030.

The previous prime is 113311312007. The next prime is 113311312033. The reversal of 113311312031 is 130213113311.

It is a strong prime.

It is an emirp because it is prime and its reverse (130213113311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113311312031 is a prime.

It is a super-2 number, since 2×113311312031² (a number of 23 digits) contains 22 as substring.

Together with 113311312033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 113311311994 and 113311312012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113311312033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655656015 + 56655656016.

It is an arithmetic number, because the mean of its divisors is an integer number (56655656016).

Almost surely, 2^113311312031 is an apocalyptic number.

113311312031 is a deficient number, since it is larger than the sum of its proper divisors (1).

113311312031 is an equidigital number, since it uses as much as digits as its factorization.

113311312031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113311312031 its reverse (130213113311), we get a palindrome (243524425342).

The spelling of 113311312031 in words is "one hundred thirteen billion, three hundred eleven million, three hundred twelve thousand, thirty-one".