Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011101010101110010011 |
3 | 1111010020122000122200102010 |
4 | 2210320330003222232103 |
5 | 2441122124104234420 |
6 | 40033241100554003 |
7 | 2246434666031325 |
oct | 244707403525623 |
9 | 44106560580363 |
10 | 11331131321235 |
11 | 3679562257670 |
12 | 1330070b52903 |
13 | 6426a0b13bab |
14 | 2b2603095615 |
15 | 149b36e634e0 |
hex | a4e3c0eab93 |
11331131321235 has 32 divisors (see below), whose sum is σ = 19779148385280. Its totient is φ = 5493555820800.
The previous prime is 11331131321183. The next prime is 11331131321267. The reversal of 11331131321235 is 53212313113311.
11331131321235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11331131321235 - 223 = 11331122932627 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 762726 + ... + 4821204.
It is an arithmetic number, because the mean of its divisors is an integer number (618098387040).
Almost surely, 211331131321235 is an apocalyptic number.
11331131321235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11331131321235 is a deficient number, since it is larger than the sum of its proper divisors (8448017064045).
11331131321235 is a wasteful number, since it uses less digits than its factorization.
11331131321235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4075419.
The product of its digits is 4860, while the sum is 30.
Adding to 11331131321235 its reverse (53212313113311), we get a palindrome (64543444434546).
The spelling of 11331131321235 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred twenty-one thousand, two hundred thirty-five".
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