11331132000019 has 4 divisors (see below), whose sum is σ = 12202757538496. Its totient is φ = 10459506461544.

The previous prime is 11331131999981. The next prime is 11331132000031. The reversal of 11331132000019 is 91000023113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11331132000019 - 2¹¹ = 11331131997971 is a prime.

It is a super-2 number, since 2×11331132000019² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331131999957 and 11331132000002.

It is not an unprimeable number, because it can be changed into a prime (11331132000079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435812769219 + ... + 435812769244.

It is an arithmetic number, because the mean of its divisors is an integer number (3050689384624).

Almost surely, 2^{11331132000019} is an apocalyptic number.

11331132000019 is a deficient number, since it is larger than the sum of its proper divisors (871625538477).

11331132000019 is an equidigital number, since it uses as much as digits as its factorization.

11331132000019 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 871625538476.

The product of its (nonzero) digits is 486, while the sum is 25.

The spelling of 11331132000019 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, nineteen", and thus it is an aban number.