11331132000407 has 2 divisors, whose sum is σ = 11331132000408. Its totient is φ = 11331132000406.

The previous prime is 11331132000371. The next prime is 11331132000479. The reversal of 11331132000407 is 70400023113311.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11331132000407 - 2¹² = 11331131996311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331132000497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000203 + 5665566000204.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566000204).

Almost surely, 2^{11331132000407} is an apocalyptic number.

11331132000407 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132000407 is an equidigital number, since it uses as much as digits as its factorization.

11331132000407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 26.

Adding to 11331132000407 its reverse (70400023113311), we get a palindrome (81731155113718).

The spelling of 11331132000407 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, four hundred seven", and thus it is an aban number.