Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110010000101111000111 |
3 | 1111010020122001221020011212 |
4 | 2210320330012100233013 |
5 | 2441122124243014343 |
6 | 40033241123322035 |
7 | 2246435004562646 |
oct | 244707406205707 |
9 | 44106561836155 |
10 | 11331132001223 |
11 | 3679562681541 |
12 | 133007122031b |
13 | 6426a0cc1558 |
14 | 2b26031d135d |
15 | 149b37049c18 |
hex | a4e3c190bc7 |
11331132001223 has 2 divisors, whose sum is σ = 11331132001224. Its totient is φ = 11331132001222.
The previous prime is 11331132001187. The next prime is 11331132001237. The reversal of 11331132001223 is 32210023113311.
It is a strong prime.
It is an emirp because it is prime and its reverse (32210023113311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331132001223 - 216 = 11331131935687 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331132001523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000611 + 5665566000612.
It is an arithmetic number, because the mean of its divisors is an integer number (5665566000612).
Almost surely, 211331132001223 is an apocalyptic number.
11331132001223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331132001223 is an equidigital number, since it uses as much as digits as its factorization.
11331132001223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11331132001223 its reverse (32210023113311), we get a palindrome (43541155114534).
The spelling of 11331132001223 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, one thousand, two hundred twenty-three".
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