11331132060013 has 2 divisors, whose sum is σ = 11331132060014. Its totient is φ = 11331132060012.

The previous prime is 11331132060007. The next prime is 11331132060029. The reversal of 11331132060013 is 31006023113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11329976196009 + 1155864004 = 3366003^2 + 33998^2 .

It is an emirp because it is prime and its reverse (31006023113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331132060013 - 2⁵ = 11331132059981 is a prime.

It is a super-3 number, since 3×11331132060013³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 11331132060013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331112060013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566030006 + 5665566030007.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566030007).

Almost surely, 2^{11331132060013} is an apocalyptic number.

It is an amenable number.

11331132060013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132060013 is an equidigital number, since it uses as much as digits as its factorization.

11331132060013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11331132060013 its reverse (31006023113311), we get a palindrome (42337155173324).

The spelling of 11331132060013 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, sixty thousand, thirteen".