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113312000030 = 2511331200003
BaseRepresentation
bin110100110000111101…
…0111110100000011110
3101211110220112000021212
41221201322332200132
53324030333000110
6124015501224422
711120656052135
oct1514172764036
9354426460255
10113312000030
1144067740819
1219b63b62112
13a8ba721238
1456ad00491c
152e32c6ae05
hex1a61ebe81e

113312000030 has 8 divisors (see below), whose sum is σ = 203961600072. Its totient is φ = 45324800008.

The previous prime is 113312000029. The next prime is 113312000033. The reversal of 113312000030 is 30000213311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 113311999969 and 113312000014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113312000033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5665599992 + ... + 5665600011.

It is an arithmetic number, because the mean of its divisors is an integer number (25495200009).

Almost surely, 2113312000030 is an apocalyptic number.

113312000030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113312000030 is a deficient number, since it is larger than the sum of its proper divisors (90649600042).

113312000030 is a wasteful number, since it uses less digits than its factorization.

113312000030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11331200010.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 113312000030 its reverse (30000213311), we get a palindrome (143312213341).

The spelling of 113312000030 in words is "one hundred thirteen billion, three hundred twelve million, thirty", and thus it is an aban number.

Divisors: 1 2 5 10 11331200003 22662400006 56656000015 113312000030