Base | Representation |
---|---|
bin | 10000011111010011011… |
… | …001101101001110111101 |
3 | 11000022210022002010110111 |
4 | 100133103121231032331 |
5 | 122031114010132201 |
6 | 2224314413110021 |
7 | 144602563455361 |
oct | 20372331551675 |
9 | 4008708063414 |
10 | 1133123130301 |
11 | 3a7611515048 |
12 | 163734788311 |
13 | 82b12206566 |
14 | 3cbb460b2a1 |
15 | 1e71d891b51 |
hex | 107d366d3bd |
1133123130301 has 2 divisors, whose sum is σ = 1133123130302. Its totient is φ = 1133123130300.
The previous prime is 1133123130299. The next prime is 1133123130383. The reversal of 1133123130301 is 1030313213311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 993470692900 + 139652437401 = 996730^2 + 373701^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133123130301 - 21 = 1133123130299 is a prime.
Together with 1133123130299, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133123130701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566561565150 + 566561565151.
It is an arithmetic number, because the mean of its divisors is an integer number (566561565151).
Almost surely, 21133123130301 is an apocalyptic number.
It is an amenable number.
1133123130301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133123130301 is an equidigital number, since it uses as much as digits as its factorization.
1133123130301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 1133123130301 its reverse (1030313213311), we get a palindrome (2163436343612).
The spelling of 1133123130301 in words is "one trillion, one hundred thirty-three billion, one hundred twenty-three million, one hundred thirty thousand, three hundred one".
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