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11331321133001 is a prime number
BaseRepresentation
bin1010010011100100011101…
…0111101111011111001001
31111010021010020211010012112
42210321013113233133021
52441123021202224001
640033312001152105
72246442462303362
oct244710727573711
944107106733175
1011331321133001
11367964a410aa1
12133010462b635
13642701241a4c
142b2620384b69
15149b48958cbb
hexa4e475ef7c9

11331321133001 has 2 divisors, whose sum is σ = 11331321133002. Its totient is φ = 11331321133000.

The previous prime is 11331321132919. The next prime is 11331321133003. The reversal of 11331321133001 is 10033112313311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8989946808976 + 2341374324025 = 2998324^2 + 1530155^2 .

It is an emirp because it is prime and its reverse (10033112313311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331321133001 is a prime.

Together with 11331321133003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11331321133003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665660566500 + 5665660566501.

It is an arithmetic number, because the mean of its divisors is an integer number (5665660566501).

Almost surely, 211331321133001 is an apocalyptic number.

It is an amenable number.

11331321133001 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331321133001 is an equidigital number, since it uses as much as digits as its factorization.

11331321133001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11331321133001 its reverse (10033112313311), we get a palindrome (21364433446312).

The spelling of 11331321133001 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, one hundred thirty-three thousand, one".