Base | Representation |
---|---|
bin | 1010010011100110111111… |
… | …1001010001010110010011 |
3 | 1111010022212122010111121112 |
4 | 2210321233321101112103 |
5 | 2441130414224323331 |
6 | 40033503245243535 |
7 | 2246465356210265 |
oct | 244715771212623 |
9 | 44108778114545 |
10 | 11332001011091 |
11 | 3679969167512 |
12 | 13302742635ab |
13 | 6427ac057387 |
14 | 2b26867a1b35 |
15 | 149b884a432b |
hex | a4e6fe51593 |
11332001011091 has 2 divisors, whose sum is σ = 11332001011092. Its totient is φ = 11332001011090.
The previous prime is 11332001011069. The next prime is 11332001011109. The reversal of 11332001011091 is 19011010023311.
It is a happy number.
Together with next prime (11332001011109) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is an emirp because it is prime and its reverse (19011010023311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11332001011091 - 242 = 6933954499987 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11332001011061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666000505545 + 5666000505546.
It is an arithmetic number, because the mean of its divisors is an integer number (5666000505546).
Almost surely, 211332001011091 is an apocalyptic number.
11332001011091 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332001011091 is an equidigital number, since it uses as much as digits as its factorization.
11332001011091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 23.
The spelling of 11332001011091 in words is "eleven trillion, three hundred thirty-two billion, one million, eleven thousand, ninety-one".
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