Base | Representation |
---|---|
bin | 110100110001001100… |
… | …1111001000110010111 |
3 | 101211111110202202022121 |
4 | 1221202121321012113 |
5 | 3324034421314333 |
6 | 124020351040411 |
7 | 11121114664645 |
oct | 1514231710627 |
9 | 354443682277 |
10 | 113320104343 |
11 | 440712766a6 |
12 | 19b66810107 |
13 | a8bc2caca4 |
14 | 56b0114195 |
15 | 2e3381c32d |
hex | 1a62679197 |
113320104343 has 2 divisors, whose sum is σ = 113320104344. Its totient is φ = 113320104342.
The previous prime is 113320104341. The next prime is 113320104367. The reversal of 113320104343 is 343401023311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113320104343 - 21 = 113320104341 is a prime.
Together with 113320104341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113320104341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660052171 + 56660052172.
It is an arithmetic number, because the mean of its divisors is an integer number (56660052172).
Almost surely, 2113320104343 is an apocalyptic number.
113320104343 is a deficient number, since it is larger than the sum of its proper divisors (1).
113320104343 is an equidigital number, since it uses as much as digits as its factorization.
113320104343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 113320104343 its reverse (343401023311), we get a palindrome (456721127654).
The spelling of 113320104343 in words is "one hundred thirteen billion, three hundred twenty million, one hundred four thousand, three hundred forty-three".
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