Base | Representation |
---|---|
bin | 110100110001001100… |
… | …1111101001110101111 |
3 | 101211111110210121112021 |
4 | 1221202121331032233 |
5 | 3324034422340023 |
6 | 124020351251011 |
7 | 11121115065166 |
oct | 1514231751657 |
9 | 354443717467 |
10 | 113320121263 |
11 | 44071288388 |
12 | 19b66819a67 |
13 | a8bc3058bb |
14 | 56b011a3dd |
15 | 2e3382235d |
hex | 1a6267d3af |
113320121263 has 2 divisors, whose sum is σ = 113320121264. Its totient is φ = 113320121262.
The previous prime is 113320121227. The next prime is 113320121303. The reversal of 113320121263 is 362121023311.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (362121023311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113320121263 - 217 = 113319990191 is a prime.
It is a super-2 number, since 2×1133201212632 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113320121063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660060631 + 56660060632.
It is an arithmetic number, because the mean of its divisors is an integer number (56660060632).
Almost surely, 2113320121263 is an apocalyptic number.
113320121263 is a deficient number, since it is larger than the sum of its proper divisors (1).
113320121263 is an equidigital number, since it uses as much as digits as its factorization.
113320121263 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 113320121263 its reverse (362121023311), we get a palindrome (475441144574).
The spelling of 113320121263 in words is "one hundred thirteen billion, three hundred twenty million, one hundred twenty-one thousand, two hundred sixty-three".
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