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113320121310 = 233511298914783
BaseRepresentation
bin110100110001001100…
…1111101001111011110
3101211111110210121121000
41221202121331033132
53324034422340220
6124020351251130
711121115065264
oct1514231751736
9354443717530
10113320121310
1144071288420
1219b66819aa6
13a8bc305926
1456b011a434
152e33822390
hex1a6267d3de

113320121310 has 256 divisors, whose sum is σ = 344881152000. Its totient is φ = 26224450560.

The previous prime is 113320121303. The next prime is 113320121311. The reversal of 113320121310 is 13121023311.

113320121310 is a `hidden beast` number, since 1 + 1 + 332 + 0 + 1 + 21 + 310 = 666.

It is a super-2 number, since 2×1133201213102 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113320121311) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 7658179 + ... + 7672961.

It is an arithmetic number, because the mean of its divisors is an integer number (1347192000).

Almost surely, 2113320121310 is an apocalyptic number.

113320121310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 113320121310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (172440576000).

113320121310 is an abundant number, since it is smaller than the sum of its proper divisors (231561030690).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113320121310 is a wasteful number, since it uses less digits than its factorization.

113320121310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14928 (or 14922 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 113320121310 its reverse (13121023311), we get a palindrome (126441144621).

It can be divided in two parts, 1133201 and 21310, that added together give a palindrome (1154511).

The spelling of 113320121310 in words is "one hundred thirteen billion, three hundred twenty million, one hundred twenty-one thousand, three hundred ten".