Search a number
-
+
113320121333 is a prime number
BaseRepresentation
bin110100110001001100…
…1111101001111110101
3101211111110210121121212
41221202121331033311
53324034422340313
6124020351251205
711121115065326
oct1514231751765
9354443717555
10113320121333
1144071288441
1219b66819b05
13a8bc305943
1456b011a44d
152e338223a8
hex1a6267d3f5

113320121333 has 2 divisors, whose sum is σ = 113320121334. Its totient is φ = 113320121332.

The previous prime is 113320121329. The next prime is 113320121351. The reversal of 113320121333 is 333121023311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111114222244 + 2205899089 = 333338^2 + 46967^2 .

It is a cyclic number.

It is not a de Polignac number, because 113320121333 - 22 = 113320121329 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113320121299 and 113320121308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113320121303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660060666 + 56660060667.

It is an arithmetic number, because the mean of its divisors is an integer number (56660060667).

Almost surely, 2113320121333 is an apocalyptic number.

It is an amenable number.

113320121333 is a deficient number, since it is larger than the sum of its proper divisors (1).

113320121333 is an equidigital number, since it uses as much as digits as its factorization.

113320121333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 113320121333 its reverse (333121023311), we get a palindrome (446441144644).

The spelling of 113320121333 in words is "one hundred thirteen billion, three hundred twenty million, one hundred twenty-one thousand, three hundred thirty-three".