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11332013111 is a prime number
BaseRepresentation
bin10101000110111000…
…01100110000110111
31002020202011220121022
422203130030300313
5141201443404421
65112244211355
7550550344046
oct124334146067
932222156538
1011332013111
1148956981a1
122243099b5b
1310b7953803
1479701855d
15464cc37ab
hex2a370cc37

11332013111 has 2 divisors, whose sum is σ = 11332013112. Its totient is φ = 11332013110.

The previous prime is 11332013101. The next prime is 11332013131. The reversal of 11332013111 is 11131023311.

11332013111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11332013111 - 26 = 11332013047 is a prime.

It is a super-2 number, since 2×113320131112 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11332013111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11332013101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666006555 + 5666006556.

It is an arithmetic number, because the mean of its divisors is an integer number (5666006556).

Almost surely, 211332013111 is an apocalyptic number.

11332013111 is a deficient number, since it is larger than the sum of its proper divisors (1).

11332013111 is an equidigital number, since it uses as much as digits as its factorization.

11332013111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11332013111 its reverse (11131023311), we get a palindrome (22463036422).

The spelling of 11332013111 in words is "eleven billion, three hundred thirty-two million, thirteen thousand, one hundred eleven".