Base | Representation |
---|---|
bin | 1010010011101000000111… |
… | …0010000001010001101111 |
3 | 1111010100122112210121101212 |
4 | 2210322001302001101233 |
5 | 2441132023040201033 |
6 | 40033553125225035 |
7 | 2246505662010422 |
oct | 244720162012157 |
9 | 44110575717355 |
10 | 11332301100143 |
11 | 367a0025a18a1 |
12 | 133033886217b |
13 | 64282928686a |
14 | 2b26b45999b9 |
15 | 149ba49ce748 |
hex | a4e81c8146f |
11332301100143 has 2 divisors, whose sum is σ = 11332301100144. Its totient is φ = 11332301100142.
The previous prime is 11332301100119. The next prime is 11332301100163. The reversal of 11332301100143 is 34100110323311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11332301100143 - 214 = 11332301083759 is a prime.
It is a super-2 number, since 2×113323011001432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11332301100163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666150550071 + 5666150550072.
It is an arithmetic number, because the mean of its divisors is an integer number (5666150550072).
Almost surely, 211332301100143 is an apocalyptic number.
11332301100143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332301100143 is an equidigital number, since it uses as much as digits as its factorization.
11332301100143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11332301100143 its reverse (34100110323311), we get a palindrome (45432411423454).
The spelling of 11332301100143 in words is "eleven trillion, three hundred thirty-two billion, three hundred one million, one hundred thousand, one hundred forty-three".
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