113323011313333 has 4 divisors (see below), whose sum is σ = 113644039674348. Its totient is φ = 113001982952320.

The previous prime is 113323011313307. The next prime is 113323011313339. The reversal of 113323011313333 is 333313110323311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 44529556264209 + 68793455049124 = 6673047^2 + 8294182^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113323011313333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113323011313295 and 113323011313304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113323011313339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160514179978 + ... + 160514180683.

It is an arithmetic number, because the mean of its divisors is an integer number (28411009918587).

Almost surely, 2^{113323011313333} is an apocalyptic number.

It is an amenable number.

113323011313333 is a deficient number, since it is larger than the sum of its proper divisors (321028361015).

113323011313333 is an equidigital number, since it uses as much as digits as its factorization.

113323011313333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 321028361014.

The product of its (nonzero) digits is 13122, while the sum is 31.

Adding to 113323011313333 its reverse (333313110323311), we get a palindrome (446636121636644).

The spelling of 113323011313333 in words is "one hundred thirteen trillion, three hundred twenty-three billion, eleven million, three hundred thirteen thousand, three hundred thirty-three".