113330122011331 has 4 divisors (see below), whose sum is σ = 114195237446664. Its totient is φ = 112465006576000.

The previous prime is 113330122011317. The next prime is 113330122011371. The reversal of 113330122011331 is 133110221033311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 113330122011331 - 2⁵ = 113330122011299 is a prime.

It is a super-3 number, since 3×113330122011331³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113330122011296 and 113330122011305.

It is not an unprimeable number, because it can be changed into a prime (113330122011371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 432557717470 + ... + 432557717731.

It is an arithmetic number, because the mean of its divisors is an integer number (28548809361666).

Almost surely, 2^{113330122011331} is an apocalyptic number.

113330122011331 is a deficient number, since it is larger than the sum of its proper divisors (865115435333).

113330122011331 is an equidigital number, since it uses as much as digits as its factorization.

113330122011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 865115435332.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 113330122011331 its reverse (133110221033311), we get a palindrome (246440343044642).

The spelling of 113330122011331 in words is "one hundred thirteen trillion, three hundred thirty billion, one hundred twenty-two million, eleven thousand, three hundred thirty-one".