Base | Representation |
---|---|
bin | 11110010001000000100011… |
… | …011100001100111101011111 |
3 | 122110022012202011121012021221 |
4 | 132101000203130030331133 |
5 | 114421334213041031221 |
6 | 1151033554044434211 |
7 | 40015616236245154 |
oct | 3621004334147537 |
9 | 573265664535257 |
10 | 133110221033311 |
11 | 3945a800662675 |
12 | 12b1979b848967 |
13 | 5937317321b12 |
14 | 24c27d777422b |
15 | 105c7804e6541 |
hex | 79102370cf5f |
133110221033311 has 4 divisors (see below), whose sum is σ = 134331415721800. Its totient is φ = 131889026344824.
The previous prime is 133110221033233. The next prime is 133110221033453. The reversal of 133110221033311 is 113330122011331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133110221033311 - 215 = 133110221000543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133110221033011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 610597344081 + ... + 610597344298.
It is an arithmetic number, because the mean of its divisors is an integer number (33582853930450).
Almost surely, 2133110221033311 is an apocalyptic number.
133110221033311 is a deficient number, since it is larger than the sum of its proper divisors (1221194688489).
133110221033311 is a wasteful number, since it uses less digits than its factorization.
133110221033311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1221194688488.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 133110221033311 its reverse (113330122011331), we get a palindrome (246440343044642).
The spelling of 133110221033311 in words is "one hundred thirty-three trillion, one hundred ten billion, two hundred twenty-one million, thirty-three thousand, three hundred eleven".
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