Base | Representation |
---|---|
bin | 10101000111000001… |
… | …00010110100001101 |
3 | 1002020211022202212212 |
4 | 22203200202310031 |
5 | 141202241331023 |
6 | 5112324440205 |
7 | 550563126341 |
oct | 124340426415 |
9 | 32224282785 |
10 | 11333152013 |
11 | 48962a5937 |
12 | 2243549065 |
13 | 10b7c62011 |
14 | 797233621 |
15 | 464e4ae78 |
hex | 2a3822d0d |
11333152013 has 2 divisors, whose sum is σ = 11333152014. Its totient is φ = 11333152012.
The previous prime is 11333152001. The next prime is 11333152049. The reversal of 11333152013 is 31025133311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5843379364 + 5489772649 = 76442^2 + 74093^2 .
It is a cyclic number.
It is not a de Polignac number, because 11333152013 - 28 = 11333151757 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11333152013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11333152073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666576006 + 5666576007.
It is an arithmetic number, because the mean of its divisors is an integer number (5666576007).
Almost surely, 211333152013 is an apocalyptic number.
It is an amenable number.
11333152013 is a deficient number, since it is larger than the sum of its proper divisors (1).
11333152013 is an equidigital number, since it uses as much as digits as its factorization.
11333152013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 11333152013 its reverse (31025133311), we get a palindrome (42358285324).
The spelling of 11333152013 in words is "eleven billion, three hundred thirty-three million, one hundred fifty-two thousand, thirteen".
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