Search a number
-
+
113332230231233 = 138717863863941
BaseRepresentation
bin11001110001001100110111…
…010100110001010011000001
3112212021110021222121110210012
4121301030313110301103001
5104323313401414344413
61041012035142114305
732604661213245116
oct3161146724612301
9485243258543705
10113332230231233
1133124a24444a02
121086466671b995
134b3125007c9b0
141ddb44869090d
15d18070e2d7a8
hex6713375314c1

113332230231233 has 4 divisors (see below), whose sum is σ = 122050094095188. Its totient is φ = 104614366367280.

The previous prime is 113332230231217. The next prime is 113332230231239. The reversal of 113332230231233 is 332132032233311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 46183006372864 + 67149223858369 = 6795808^2 + 8194463^2 .

It is a cyclic number.

It is not a de Polignac number, because 113332230231233 - 24 = 113332230231217 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113332230231233.

It is not an unprimeable number, because it can be changed into a prime (113332230231239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4358931931958 + ... + 4358931931983.

It is an arithmetic number, because the mean of its divisors is an integer number (30512523523797).

Almost surely, 2113332230231233 is an apocalyptic number.

113332230231233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

113332230231233 is a deficient number, since it is larger than the sum of its proper divisors (8717863863955).

113332230231233 is an equidigital number, since it uses as much as digits as its factorization.

113332230231233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8717863863954.

The product of its (nonzero) digits is 34992, while the sum is 32.

Adding to 113332230231233 its reverse (332132032233311), we get a palindrome (445464262464544).

The spelling of 113332230231233 in words is "one hundred thirteen trillion, three hundred thirty-two billion, two hundred thirty million, two hundred thirty-one thousand, two hundred thirty-three".

Divisors: 1 13 8717863863941 113332230231233