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113333000114951 is a prime number
BaseRepresentation
bin11001110001001101100101…
…001101101001001100000111
3112212021112021122021121200222
4121301031211031221030013
5104323321441012134301
61041012243403254555
732605016252200061
oct3161154515511407
9485245248247628
10113333000114951
1133125289a85a41
121086484051a45b
134b313437199a6
141ddb4bca1a731
15d180b880731b
hex671365369307

113333000114951 has 2 divisors, whose sum is σ = 113333000114952. Its totient is φ = 113333000114950.

The previous prime is 113333000114899. The next prime is 113333000114963. The reversal of 113333000114951 is 159411000333311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 113333000114951 - 222 = 113332995920647 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113333000114251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56666500057475 + 56666500057476.

It is an arithmetic number, because the mean of its divisors is an integer number (56666500057476).

Almost surely, 2113333000114951 is an apocalyptic number.

113333000114951 is a deficient number, since it is larger than the sum of its proper divisors (1).

113333000114951 is an equidigital number, since it uses as much as digits as its factorization.

113333000114951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14580, while the sum is 35.

The spelling of 113333000114951 in words is "one hundred thirteen trillion, three hundred thirty-three billion, one hundred fourteen thousand, nine hundred fifty-one".