Base | Representation |
---|---|
bin | 1010010011101110011100… |
… | …1010111100010010001111 |
3 | 1111010112001002120222120212 |
4 | 2210323213022330102033 |
5 | 2441144014021211421 |
6 | 40034434012233035 |
7 | 2246566065361331 |
oct | 244734712742217 |
9 | 44115032528525 |
10 | 11334002132111 |
11 | 367a7a57aa33a |
12 | 133073246b77b |
13 | 642a3a804a59 |
14 | 2b27d646d451 |
15 | 149c53ed8e5b |
hex | a4ee72bc48f |
11334002132111 has 4 divisors (see below), whose sum is σ = 11334052919952. Its totient is φ = 11333951344272.
The previous prime is 11334002132081. The next prime is 11334002132143. The reversal of 11334002132111 is 11123120043311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11334002132111 is a prime.
It is a super-3 number, since 3×113340021321113 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11334002132611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25057691 + ... + 25505996.
It is an arithmetic number, because the mean of its divisors is an integer number (2833513229988).
Almost surely, 211334002132111 is an apocalyptic number.
11334002132111 is a deficient number, since it is larger than the sum of its proper divisors (50787841).
11334002132111 is an equidigital number, since it uses as much as digits as its factorization.
11334002132111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50787840.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 11334002132111 its reverse (11123120043311), we get a palindrome (22457122175422).
The spelling of 11334002132111 in words is "eleven trillion, three hundred thirty-four billion, two million, one hundred thirty-two thousand, one hundred eleven".
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