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1133440324342 = 2566720162171
BaseRepresentation
bin10000011111100110010…
…011101101001011110110
311000100121101221020212221
4100133212103231023312
5122032241210334332
62224410103432554
7144613464536344
oct20374623551366
94010541836787
101133440324342
113a7764572687
12163802a5575a
1382b62b44541
143cc047b8994
151e73b64a297
hex107e64ed2f6

1133440324342 has 4 divisors (see below), whose sum is σ = 1700160486516. Its totient is φ = 566720162170.

The previous prime is 1133440324333. The next prime is 1133440324351. The reversal of 1133440324342 is 2434230443311.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1133440324333) and next prime (1133440324351).

It is a junction number, because it is equal to n+sod(n) for n = 1133440324298 and 1133440324307.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 283360081084 + ... + 283360081087.

It is an arithmetic number, because the mean of its divisors is an integer number (425040121629).

Almost surely, 21133440324342 is an apocalyptic number.

1133440324342 is a deficient number, since it is larger than the sum of its proper divisors (566720162174).

1133440324342 is an equidigital number, since it uses as much as digits as its factorization.

1133440324342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 566720162173.

The product of its (nonzero) digits is 82944, while the sum is 34.

Adding to 1133440324342 its reverse (2434230443311), we get a palindrome (3567670767653).

The spelling of 1133440324342 in words is "one trillion, one hundred thirty-three billion, four hundred forty million, three hundred twenty-four thousand, three hundred forty-two".

Divisors: 1 2 566720162171 1133440324342