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1133441203334 = 211175329389649
BaseRepresentation
bin10000011111100110010…
…111000011110010000110
311000100121110120220122012
4100133212113003302012
5122032241422001314
62224410134334222
7144613505160116
oct20374627036206
94010543526565
101133441203334
113a7765013020
121638031ba372
1382b6309165b
143cc04967046
151e73b77093e
hex107e65c3c86

1133441203334 has 16 divisors (see below), whose sum is σ = 1855780059600. Its totient is φ = 514906632960.

The previous prime is 1133441203333. The next prime is 1133441203423. The reversal of 1133441203334 is 4333021443311.

It is a happy number.

It is a super-2 number, since 2×11334412033342 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1133441203334.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1133441203333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14656259 + ... + 14733390.

It is an arithmetic number, because the mean of its divisors is an integer number (115986253725).

Almost surely, 21133441203334 is an apocalyptic number.

1133441203334 is a deficient number, since it is larger than the sum of its proper divisors (722338856266).

1133441203334 is a wasteful number, since it uses less digits than its factorization.

1133441203334 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29391415.

The product of its (nonzero) digits is 31104, while the sum is 32.

Adding to 1133441203334 its reverse (4333021443311), we get a palindrome (5466462646645).

The spelling of 1133441203334 in words is "one trillion, one hundred thirty-three billion, four hundred forty-one million, two hundred three thousand, three hundred thirty-four".

Divisors: 1 2 11 22 1753 3506 19283 38566 29389649 58779298 323286139 646572278 51520054697 103040109394 566720601667 1133441203334