Base | Representation |
---|---|
bin | 1010010011110011000101… |
… | …0001110001001000011101 |
3 | 1111010122020202002100002121 |
4 | 2210330301101301020131 |
5 | 2441204040312413141 |
6 | 40035201224422541 |
7 | 2246641643313325 |
oct | 244746121611035 |
9 | 44118222070077 |
10 | 11335245435421 |
11 | 36802835a2536 |
12 | 1330a1a917a51 |
13 | 642ba827b49b |
14 | 2b28b3632285 |
15 | 149cc822a1d1 |
hex | a4f3147121d |
11335245435421 has 2 divisors, whose sum is σ = 11335245435422. Its totient is φ = 11335245435420.
The previous prime is 11335245435373. The next prime is 11335245435427. The reversal of 11335245435421 is 12453454253311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6081225048196 + 5254020387225 = 2466014^2 + 2292165^2 .
It is a cyclic number.
It is not a de Polignac number, because 11335245435421 - 211 = 11335245433373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11335245435427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667622717710 + 5667622717711.
It is an arithmetic number, because the mean of its divisors is an integer number (5667622717711).
Almost surely, 211335245435421 is an apocalyptic number.
It is an amenable number.
11335245435421 is a deficient number, since it is larger than the sum of its proper divisors (1).
11335245435421 is an equidigital number, since it uses as much as digits as its factorization.
11335245435421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 864000, while the sum is 43.
Adding to 11335245435421 its reverse (12453454253311), we get a palindrome (23788699688732).
The spelling of 11335245435421 in words is "eleven trillion, three hundred thirty-five billion, two hundred forty-five million, four hundred thirty-five thousand, four hundred twenty-one".
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