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11335305103 = 83136569941
BaseRepresentation
bin10101000111010001…
…10000011110001111
31002020222101011100221
422203220300132033
5141203314230403
65112442532211
7550620334513
oct124350603617
932228334327
1011335305103
114897536551
122244207067
1310b8537035
14797634143
15465223dbd
hex2a3a3078f

11335305103 has 4 divisors (see below), whose sum is σ = 11471875128. Its totient is φ = 11198735080.

The previous prime is 11335305071. The next prime is 11335305127. The reversal of 11335305103 is 30150353311.

11335305103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11335305103 - 25 = 11335305071 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11335305503) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68284888 + ... + 68285053.

It is an arithmetic number, because the mean of its divisors is an integer number (2867968782).

Almost surely, 211335305103 is an apocalyptic number.

11335305103 is a deficient number, since it is larger than the sum of its proper divisors (136570025).

11335305103 is an equidigital number, since it uses as much as digits as its factorization.

11335305103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 136570024.

The product of its (nonzero) digits is 2025, while the sum is 25.

Adding to 11335305103 its reverse (30150353311), we get a palindrome (41485658414).

The spelling of 11335305103 in words is "eleven billion, three hundred thirty-five million, three hundred five thousand, one hundred three".

Divisors: 1 83 136569941 11335305103