Base | Representation |
---|---|
bin | 1010010011110011010100… |
… | …1111110110010000101001 |
3 | 1111010122102101102020202221 |
4 | 2210330311033312100221 |
5 | 2441204204340303001 |
6 | 40035212004154041 |
7 | 2246643412411564 |
oct | 244746517662051 |
9 | 44118371366687 |
10 | 11335312041001 |
11 | 3680308155273 |
12 | 1330a39098921 |
13 | 642bb8ccbc80 |
14 | 2b28bc40d4db |
15 | 149ccded51a1 |
hex | a4f353f6429 |
11335312041001 has 16 divisors (see below), whose sum is σ = 13025770387840. Its totient is φ = 9776871642240.
The previous prime is 11335312040993. The next prime is 11335312041043. The reversal of 11335312041001 is 10014021353311.
It is a cyclic number.
It is not a de Polignac number, because 11335312041001 - 23 = 11335312040993 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11335312041071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 314310405 + ... + 314346466.
It is an arithmetic number, because the mean of its divisors is an integer number (814110649240).
Almost surely, 211335312041001 is an apocalyptic number.
It is an amenable number.
11335312041001 is a deficient number, since it is larger than the sum of its proper divisors (1690458346839).
11335312041001 is a wasteful number, since it uses less digits than its factorization.
11335312041001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 628656976.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 11335312041001 its reverse (10014021353311), we get a palindrome (21349333394312).
The spelling of 11335312041001 in words is "eleven trillion, three hundred thirty-five billion, three hundred twelve million, forty-one thousand, one".
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