1134014133433 has 4 divisors (see below), whose sum is σ = 1134243835380. Its totient is φ = 1133784431488.

The previous prime is 1134014133419. The next prime is 1134014133503. The reversal of 1134014133433 is 3343314104311.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 640947550464 + 493066582969 = 800592^2 + 702187^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1134014133433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1134014133395 and 1134014133404.

It is not an unprimeable number, because it can be changed into a prime (1134014173433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114843568 + ... + 114853441.

It is an arithmetic number, because the mean of its divisors is an integer number (283560958845).

Almost surely, 2^{1134014133433} is an apocalyptic number.

It is an amenable number.

1134014133433 is a deficient number, since it is larger than the sum of its proper divisors (229701947).

1134014133433 is an equidigital number, since it uses as much as digits as its factorization.

1134014133433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 229701946.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 1134014133433 its reverse (3343314104311), we get a palindrome (4477328237744).

The spelling of 1134014133433 in words is "one trillion, one hundred thirty-four billion, fourteen million, one hundred thirty-three thousand, four hundred thirty-three".