Search a number
-
+
113402100113 is a prime number
BaseRepresentation
bin110100110011101001…
…0101011100110010001
3101211201012001120100222
41221213102223212101
53324221414200423
6124032440322425
711123131642451
oct1514722534621
9354635046328
10113402100113
11441035902a5
1219b8a173415
13a9032a98b3
1456bad79d61
152e3ab173c8
hex1a674ab991

113402100113 has 2 divisors, whose sum is σ = 113402100114. Its totient is φ = 113402100112.

The previous prime is 113402100103. The next prime is 113402100169. The reversal of 113402100113 is 311001204311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94017664129 + 19384435984 = 306623^2 + 139228^2 .

It is a cyclic number.

It is not a de Polignac number, because 113402100113 - 226 = 113334991249 is a prime.

It is a super-2 number, since 2×1134021001132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113402100091 and 113402100100.

It is not a weakly prime, because it can be changed into another prime (113402100103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56701050056 + 56701050057.

It is an arithmetic number, because the mean of its divisors is an integer number (56701050057).

Almost surely, 2113402100113 is an apocalyptic number.

It is an amenable number.

113402100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113402100113 is an equidigital number, since it uses as much as digits as its factorization.

113402100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 113402100113 its reverse (311001204311), we get a palindrome (424403304424).

The spelling of 113402100113 in words is "one hundred thirteen billion, four hundred two million, one hundred thousand, one hundred thirteen".