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11341004147 = 112175513371
BaseRepresentation
bin10101000111111100…
…11111110101110011
31002021101002200222122
422203332133311303
5141211244113042
65113205024455
7551016642014
oct124376376563
932241080878
1011341004147
11489a779300
1222460b512b
1310b9781055
147982b900b
1546599c7d2
hex2a3f9fd73

11341004147 has 12 divisors (see below), whose sum is σ = 13199012568. Its totient is φ = 9703531200.

The previous prime is 11341004111. The next prime is 11341004159. The reversal of 11341004147 is 74140014311.

It is not a de Polignac number, because 11341004147 - 218 = 11340742003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11341004747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2754629 + ... + 2758742.

It is an arithmetic number, because the mean of its divisors is an integer number (1099917714).

Almost surely, 211341004147 is an apocalyptic number.

11341004147 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

11341004147 is a deficient number, since it is larger than the sum of its proper divisors (1858008421).

11341004147 is a wasteful number, since it uses less digits than its factorization.

11341004147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5513410 (or 5513399 counting only the distinct ones).

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 11341004147 its reverse (74140014311), we get a palindrome (85481018458).

The spelling of 11341004147 in words is "eleven billion, three hundred forty-one million, four thousand, one hundred forty-seven".

Divisors: 1 11 17 121 187 2057 5513371 60647081 93727307 667117891 1031000377 11341004147