Base | Representation |
---|---|
bin | 10101000111111100… |
… | …11111110101110011 |
3 | 1002021101002200222122 |
4 | 22203332133311303 |
5 | 141211244113042 |
6 | 5113205024455 |
7 | 551016642014 |
oct | 124376376563 |
9 | 32241080878 |
10 | 11341004147 |
11 | 489a779300 |
12 | 22460b512b |
13 | 10b9781055 |
14 | 7982b900b |
15 | 46599c7d2 |
hex | 2a3f9fd73 |
11341004147 has 12 divisors (see below), whose sum is σ = 13199012568. Its totient is φ = 9703531200.
The previous prime is 11341004111. The next prime is 11341004159. The reversal of 11341004147 is 74140014311.
It is not a de Polignac number, because 11341004147 - 218 = 11340742003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11341004747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2754629 + ... + 2758742.
It is an arithmetic number, because the mean of its divisors is an integer number (1099917714).
Almost surely, 211341004147 is an apocalyptic number.
11341004147 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
11341004147 is a deficient number, since it is larger than the sum of its proper divisors (1858008421).
11341004147 is a wasteful number, since it uses less digits than its factorization.
11341004147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5513410 (or 5513399 counting only the distinct ones).
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 11341004147 its reverse (74140014311), we get a palindrome (85481018458).
The spelling of 11341004147 in words is "eleven billion, three hundred forty-one million, four thousand, one hundred forty-seven".
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