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1134110343413 is a prime number
BaseRepresentation
bin10000100000001110001…
…111101000000011110101
311000102100002200202021002
4100200032033220003311
5122040124221442123
62225000400333045
7144636211601615
oct20401617500365
94012302622232
101134110343413
113a7a787a4953
1216396b314185
1382c3b8b7528
143cc6978aa45
151e77a399528
hex1080e3e80f5

1134110343413 has 2 divisors, whose sum is σ = 1134110343414. Its totient is φ = 1134110343412.

The previous prime is 1134110343389. The next prime is 1134110343433. The reversal of 1134110343413 is 3143430114311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1063740578884 + 70369764529 = 1031378^2 + 265273^2 .

It is a cyclic number.

It is not a de Polignac number, because 1134110343413 - 210 = 1134110342389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1134110343433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567055171706 + 567055171707.

It is an arithmetic number, because the mean of its divisors is an integer number (567055171707).

Almost surely, 21134110343413 is an apocalyptic number.

It is an amenable number.

1134110343413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134110343413 is an equidigital number, since it uses as much as digits as its factorization.

1134110343413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1134110343413 its reverse (3143430114311), we get a palindrome (4277540457724).

The spelling of 1134110343413 in words is "one trillion, one hundred thirty-four billion, one hundred ten million, three hundred forty-three thousand, four hundred thirteen".