Base | Representation |
---|---|
bin | 110100110011111010… |
… | …1100101111101010111 |
3 | 101211201211021112110210 |
4 | 1221213311211331113 |
5 | 3324231240031210 |
6 | 124033404420503 |
7 | 11123302510503 |
oct | 1514765457527 |
9 | 354654245423 |
10 | 113411252055 |
11 | 44108771292 |
12 | 19b91247733 |
13 | a90516244a |
14 | 56bc27d303 |
15 | 2e3b823e20 |
hex | 1a67d65f57 |
113411252055 has 16 divisors (see below), whose sum is σ = 182127596544. Its totient is φ = 60262803360.
The previous prime is 113411252039. The next prime is 113411252089. The reversal of 113411252055 is 550252114311.
It is not a de Polignac number, because 113411252055 - 24 = 113411252039 is a prime.
It is a super-2 number, since 2×1134112520552 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13945659 + ... + 13953788.
It is an arithmetic number, because the mean of its divisors is an integer number (11382974784).
Almost surely, 2113411252055 is an apocalyptic number.
113411252055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
113411252055 is a deficient number, since it is larger than the sum of its proper divisors (68716344489).
113411252055 is a wasteful number, since it uses less digits than its factorization.
113411252055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27899726.
The product of its (nonzero) digits is 6000, while the sum is 30.
Adding to 113411252055 its reverse (550252114311), we get a palindrome (663663366366).
The spelling of 113411252055 in words is "one hundred thirteen billion, four hundred eleven million, two hundred fifty-two thousand, fifty-five".
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