Base | Representation |
---|---|
bin | 10101000111111110… |
… | …10100110100000111 |
3 | 1002021101111201121221 |
4 | 22203333110310013 |
5 | 141211323034002 |
6 | 5113213421211 |
7 | 551021534425 |
oct | 124377246407 |
9 | 32241451557 |
10 | 11341221127 |
11 | 489a907325 |
12 | 224619a807 |
13 | 10b9828a42 |
14 | 798334115 |
15 | 4659e1c37 |
hex | 2a3fd4d07 |
11341221127 has 2 divisors, whose sum is σ = 11341221128. Its totient is φ = 11341221126.
The previous prime is 11341221113. The next prime is 11341221149. The reversal of 11341221127 is 72112214311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11341221127 - 211 = 11341219079 is a prime.
It is a super-2 number, since 2×113412211272 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11341221187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670610563 + 5670610564.
It is an arithmetic number, because the mean of its divisors is an integer number (5670610564).
Almost surely, 211341221127 is an apocalyptic number.
11341221127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341221127 is an equidigital number, since it uses as much as digits as its factorization.
11341221127 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 672, while the sum is 25.
Adding to 11341221127 its reverse (72112214311), we get a palindrome (83453435438).
The spelling of 11341221127 in words is "eleven billion, three hundred forty-one million, two hundred twenty-one thousand, one hundred twenty-seven".
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