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113412554413 is a prime number
BaseRepresentation
bin110100110011111101…
…0100011111010101101
3101211201220201200222021
41221213322203322231
53324232103220123
6124033452350141
711123316543454
oct1514772437255
9354656650867
10113412554413
1144109480814
1219b91775351
13a9054ca182
1456bc4dbb9b
152e3b9cec5d
hex1a67ea3ead

113412554413 has 2 divisors, whose sum is σ = 113412554414. Its totient is φ = 113412554412.

The previous prime is 113412554357. The next prime is 113412554419. The reversal of 113412554413 is 314455214311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83994473124 + 29418081289 = 289818^2 + 171517^2 .

It is a cyclic number.

It is not a de Polignac number, because 113412554413 - 221 = 113410457261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113412554419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56706277206 + 56706277207.

It is an arithmetic number, because the mean of its divisors is an integer number (56706277207).

Almost surely, 2113412554413 is an apocalyptic number.

It is an amenable number.

113412554413 is a deficient number, since it is larger than the sum of its proper divisors (1).

113412554413 is an equidigital number, since it uses as much as digits as its factorization.

113412554413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 28800, while the sum is 34.

Adding to 113412554413 its reverse (314455214311), we get a palindrome (427867768724).

The spelling of 113412554413 in words is "one hundred thirteen billion, four hundred twelve million, five hundred fifty-four thousand, four hundred thirteen".