1134214324433 has 2 divisors, whose sum is σ = 1134214324434. Its totient is φ = 1134214324432.

The previous prime is 1134214324409. The next prime is 1134214324457. The reversal of 1134214324433 is 3344234124311.

It is a balanced prime because it is at equal distance from previous prime (1134214324409) and next prime (1134214324457).

It can be written as a sum of positive squares in only one way, i.e., 1133166637009 + 1047687424 = 1064503^2 + 32368^2 .

It is an emirp because it is prime and its reverse (3344234124311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1134214324433 - 2³⁴ = 1117034455249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1134214324393 and 1134214324402.

It is not a weakly prime, because it can be changed into another prime (1134214324403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567107162216 + 567107162217.

It is an arithmetic number, because the mean of its divisors is an integer number (567107162217).

Almost surely, 2^{1134214324433} is an apocalyptic number.

It is an amenable number.

1134214324433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134214324433 is an equidigital number, since it uses as much as digits as its factorization.

1134214324433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 82944, while the sum is 35.

Adding to 1134214324433 its reverse (3344234124311), we get a palindrome (4478448448744).

The spelling of 1134214324433 in words is "one trillion, one hundred thirty-four billion, two hundred fourteen million, three hundred twenty-four thousand, four hundred thirty-three".