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1134220130251 = 13194591984333
BaseRepresentation
bin10000100000010100110…
…010011011011111001011
311000102121202021111111021
4100200110302123133023
5122040340323132001
62225015321413311
7144642014015065
oct20402462333713
94012552244437
101134220130251
113a802477037a
121639a003a237
1382c58576860
143cc7a1a8735
151e784d33ba1
hex10814c9b7cb

1134220130251 has 8 divisors (see below), whose sum is σ = 1285755613520. Its totient is φ = 991868615712.

The previous prime is 1134220130249. The next prime is 1134220130359. The reversal of 1134220130251 is 1520310224311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1134220130251 - 21 = 1134220130249 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1134220131251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2295991920 + ... + 2295992413.

It is an arithmetic number, because the mean of its divisors is an integer number (160719451690).

Almost surely, 21134220130251 is an apocalyptic number.

1134220130251 is a deficient number, since it is larger than the sum of its proper divisors (151535483269).

1134220130251 is a wasteful number, since it uses less digits than its factorization.

1134220130251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4591984365.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 1134220130251 its reverse (1520310224311), we get a palindrome (2654530354562).

The spelling of 1134220130251 in words is "one trillion, one hundred thirty-four billion, two hundred twenty million, one hundred thirty thousand, two hundred fifty-one".

Divisors: 1 13 19 247 4591984333 59695796329 87247702327 1134220130251