Base | Representation |
---|---|
bin | 10101001000000111… |
… | …10111101011110111 |
3 | 1002021110202020221011 |
4 | 22210003313223313 |
5 | 141212124200120 |
6 | 5113255133051 |
7 | 551034626056 |
oct | 124403675367 |
9 | 32243666834 |
10 | 11342412535 |
11 | 48a0550463 |
12 | 2246674187 |
13 | 10b9b5510c |
14 | 79856439d |
15 | 465b79c5a |
hex | 2a40f7af7 |
11342412535 has 8 divisors (see below), whose sum is σ = 13613440176. Its totient is φ = 9072233280.
The previous prime is 11342412467. The next prime is 11342412551. The reversal of 11342412535 is 53521424311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11342412535 - 215 = 11342379767 is a prime.
It is a super-2 number, since 2×113424125352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11342412497 and 11342412506.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182301 + ... + 236470.
It is an arithmetic number, because the mean of its divisors is an integer number (1701680022).
Almost surely, 211342412535 is an apocalyptic number.
11342412535 is a deficient number, since it is larger than the sum of its proper divisors (2271027641).
11342412535 is an equidigital number, since it uses as much as digits as its factorization.
11342412535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 424193.
The product of its digits is 14400, while the sum is 31.
Adding to 11342412535 its reverse (53521424311), we get a palindrome (64863836846).
The spelling of 11342412535 in words is "eleven billion, three hundred forty-two million, four hundred twelve thousand, five hundred thirty-five".
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