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11343100103 is a prime number
BaseRepresentation
bin10101001000001100…
…11111100011000111
31002021112001012002122
422210012133203013
5141212313200403
65113322000155
7551043521456
oct124406374307
932245035078
1011343100103
1148a097aaa5
12224694605b
1310ba03606a
147986a2b9d
15465c63838
hex2a419f8c7

11343100103 has 2 divisors, whose sum is σ = 11343100104. Its totient is φ = 11343100102.

The previous prime is 11343100099. The next prime is 11343100127. The reversal of 11343100103 is 30100134311.

11343100103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11343100103 - 22 = 11343100099 is a prime.

It is a super-2 number, since 2×113431001032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11343100133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671550051 + 5671550052.

It is an arithmetic number, because the mean of its divisors is an integer number (5671550052).

Almost surely, 211343100103 is an apocalyptic number.

11343100103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11343100103 is an equidigital number, since it uses as much as digits as its factorization.

11343100103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11343100103 its reverse (30100134311), we get a palindrome (41443234414).

The spelling of 11343100103 in words is "eleven billion, three hundred forty-three million, one hundred thousand, one hundred three".