1134311204003 has 4 divisors (see below), whose sum is σ = 1134345642360. Its totient is φ = 1134276765648.

The previous prime is 1134311203999. The next prime is 1134311204023. The reversal of 1134311204003 is 3004021134311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1134311204003 - 2² = 1134311203999 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1134311204003.

It is not an unprimeable number, because it can be changed into a prime (1134311204023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17169725 + ... + 17235662.

It is an arithmetic number, because the mean of its divisors is an integer number (283586410590).

Almost surely, 2^{1134311204003} is an apocalyptic number.

1134311204003 is a deficient number, since it is larger than the sum of its proper divisors (34438357).

1134311204003 is an equidigital number, since it uses as much as digits as its factorization.

1134311204003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34438356.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1134311204003 its reverse (3004021134311), we get a palindrome (4138332338314).

The spelling of 1134311204003 in words is "one trillion, one hundred thirty-four billion, three hundred eleven million, two hundred four thousand, three".