Base | Representation |
---|---|
bin | 10101001000001101… |
… | …00111001010111100 |
3 | 1002021112002202220222 |
4 | 22210012213022330 |
5 | 141212320200244 |
6 | 5113322400512 |
7 | 551044011500 |
oct | 124406471274 |
9 | 32245082828 |
10 | 11343131324 |
11 | 48a09a14a8 |
12 | 2246960138 |
13 | 10ba047335 |
14 | 7986b0300 |
15 | 465c6cbee |
hex | 2a41a72bc |
11343131324 has 18 divisors (see below), whose sum is σ = 23091374880. Its totient is φ = 4861341912.
The previous prime is 11343131321. The next prime is 11343131333. The reversal of 11343131324 is 42313134311.
It is a junction number, because it is equal to n+sod(n) for n = 11343131293 and 11343131302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11343131321) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 28936364 + ... + 28936755.
It is an arithmetic number, because the mean of its divisors is an integer number (1282854160).
Almost surely, 211343131324 is an apocalyptic number.
11343131324 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
11343131324 is an abundant number, since it is smaller than the sum of its proper divisors (11748243556).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11343131324 is a wasteful number, since it uses less digits than its factorization.
11343131324 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57873137 (or 57873128 counting only the distinct ones).
The product of its digits is 2592, while the sum is 26.
Adding to 11343131324 its reverse (42313134311), we get a palindrome (53656265635).
The spelling of 11343131324 in words is "eleven billion, three hundred forty-three million, one hundred thirty-one thousand, three hundred twenty-four".
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