Base | Representation |
---|---|
bin | 10000100000011010111… |
… | …100111100110101000011 |
3 | 11000102212221212211211221 |
4 | 100200122330330311003 |
5 | 122041043312122210 |
6 | 2225033454215511 |
7 | 144644411046655 |
oct | 20403274746503 |
9 | 4012787784757 |
10 | 1134323551555 |
11 | 3a8078089327 |
12 | 163a0a7b4597 |
13 | 82c73b176ac |
14 | 3cc89c0a6d5 |
15 | 1e78de621da |
hex | 1081af3cd43 |
1134323551555 has 32 divisors (see below), whose sum is σ = 1429406714880. Its totient is φ = 862487725440.
The previous prime is 1134323551547. The next prime is 1134323551607. The reversal of 1134323551555 is 5551553234311.
It is not a de Polignac number, because 1134323551555 - 23 = 1134323551547 is a prime.
It is a super-2 number, since 2×11343235515552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36412176 + ... + 36443314.
It is an arithmetic number, because the mean of its divisors is an integer number (44668959840).
Almost surely, 21134323551555 is an apocalyptic number.
1134323551555 is a deficient number, since it is larger than the sum of its proper divisors (295083163325).
1134323551555 is a wasteful number, since it uses less digits than its factorization.
1134323551555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33171.
The product of its digits is 675000, while the sum is 43.
Adding to 1134323551555 its reverse (5551553234311), we get a palindrome (6685876785866).
The spelling of 1134323551555 in words is "one trillion, one hundred thirty-four billion, three hundred twenty-three million, five hundred fifty-one thousand, five hundred fifty-five".
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