Base | Representation |
---|---|
bin | 10101001000001110… |
… | …10010110111100101 |
3 | 1002021112102212110001 |
4 | 22210013102313211 |
5 | 141212341412214 |
6 | 5113330301301 |
7 | 551045355352 |
oct | 124407226745 |
9 | 32245385401 |
10 | 11343310309 |
11 | 48a1003a21 |
12 | 2246a27831 |
13 | 10ba0aa946 |
14 | 798719629 |
15 | 465ca5c74 |
hex | 2a41d2de5 |
11343310309 has 2 divisors, whose sum is σ = 11343310310. Its totient is φ = 11343310308.
The previous prime is 11343310291. The next prime is 11343310331. The reversal of 11343310309 is 90301334311.
11343310309 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6947222500 + 4396087809 = 83350^2 + 66303^2 .
It is a cyclic number.
It is not a de Polignac number, because 11343310309 - 29 = 11343309797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11343310339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5671655154 + 5671655155.
It is an arithmetic number, because the mean of its divisors is an integer number (5671655155).
Almost surely, 211343310309 is an apocalyptic number.
It is an amenable number.
11343310309 is a deficient number, since it is larger than the sum of its proper divisors (1).
11343310309 is an equidigital number, since it uses as much as digits as its factorization.
11343310309 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2916, while the sum is 28.
The spelling of 11343310309 in words is "eleven billion, three hundred forty-three million, three hundred ten thousand, three hundred nine".
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