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113433123301 is a prime number
BaseRepresentation
bin110100110100100100…
…1000001100111100101
3101211210100102201011221
41221221021001213211
53324302334421201
6124035505300341
711123656432201
oct1515111014745
9354710381157
10113433123301
114411a04a4a3
1219b986346b1
13a90984c504
1456c1133b01
152e3d6e44a1
hex1a692419e5

113433123301 has 2 divisors, whose sum is σ = 113433123302. Its totient is φ = 113433123300.

The previous prime is 113433123289. The next prime is 113433123317. The reversal of 113433123301 is 103321334311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 108223892676 + 5209230625 = 328974^2 + 72175^2 .

It is a cyclic number.

It is not a de Polignac number, because 113433123301 - 25 = 113433123269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113433123361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716561650 + 56716561651.

It is an arithmetic number, because the mean of its divisors is an integer number (56716561651).

Almost surely, 2113433123301 is an apocalyptic number.

It is an amenable number.

113433123301 is a deficient number, since it is larger than the sum of its proper divisors (1).

113433123301 is an equidigital number, since it uses as much as digits as its factorization.

113433123301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 113433123301 its reverse (103321334311), we get a palindrome (216754457612).

The spelling of 113433123301 in words is "one hundred thirteen billion, four hundred thirty-three million, one hundred twenty-three thousand, three hundred one".