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113433301 is a prime number
BaseRepresentation
bin1101100001011…
…01101011010101
321220110000020101
412300231223111
5213014331201
615131134101
72545111222
oct660555325
9256400211
10113433301
1159037133
1231ba4331
131a667cc7
14110ca949
159e59d01
hex6c2dad5

113433301 has 2 divisors, whose sum is σ = 113433302. Its totient is φ = 113433300.

The previous prime is 113433277. The next prime is 113433311. The reversal of 113433301 is 103334311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 93586276 + 19847025 = 9674^2 + 4455^2 .

It is a cyclic number.

It is not a de Polignac number, because 113433301 - 221 = 111336149 is a prime.

It is a super-2 number, since 2×1134333012 = 25734227551513202, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113433311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56716650 + 56716651.

It is an arithmetic number, because the mean of its divisors is an integer number (56716651).

Almost surely, 2113433301 is an apocalyptic number.

It is an amenable number.

113433301 is a deficient number, since it is larger than the sum of its proper divisors (1).

113433301 is an equidigital number, since it uses as much as digits as its factorization.

113433301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 19.

The square root of 113433301 is about 10650.5070771302. The cubic root of 113433301 is about 484.0759690533.

Adding to 113433301 its reverse (103334311), we get a palindrome (216767612).

The spelling of 113433301 in words is "one hundred thirteen million, four hundred thirty-three thousand, three hundred one".