1134334013 has 2 divisors, whose sum is σ = 1134334014. Its totient is φ = 1134334012.

The previous prime is 1134333983. The next prime is 1134334031. The reversal of 1134334013 is 3104334311.

Together with next prime (1134334031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1128825604 + 5508409 = 33598^2 + 2347^2 .

It is a cyclic number.

It is not a de Polignac number, because 1134334013 - 2²⁰ = 1133285437 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1134334013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1134334093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567167006 + 567167007.

It is an arithmetic number, because the mean of its divisors is an integer number (567167007).

Almost surely, 2^1134334013 is an apocalyptic number.

It is an amenable number.

1134334013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1134334013 is an equidigital number, since it uses as much as digits as its factorization.

1134334013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

The square root of 1134334013 is about 33679.8754896748. The cubic root of 1134334013 is about 1042.9103677264.

Adding to 1134334013 its reverse (3104334311), we get a palindrome (4238668324).

The spelling of 1134334013 in words is "one billion, one hundred thirty-four million, three hundred thirty-four thousand, thirteen".