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11343343314 = 231890557219
BaseRepresentation
bin10101001000001110…
…11010111011010010
31002021112111112201110
422210013122323102
5141212343441224
65113331114150
7551045553522
oct124407327322
932245445643
1011343343314
1148a10267a6
122246a42956
1310ba0bc984
14798727682
15465cb0929
hex2a41daed2

11343343314 has 8 divisors (see below), whose sum is σ = 22686686640. Its totient is φ = 3781114436.

The previous prime is 11343343309. The next prime is 11343343327. The reversal of 11343343314 is 41334334311.

11343343314 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

11343343314 is an admirable number.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 945278604 + ... + 945278615.

It is an arithmetic number, because the mean of its divisors is an integer number (2835835830).

Almost surely, 211343343314 is an apocalyptic number.

11343343314 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11343343314 is a wasteful number, since it uses less digits than its factorization.

11343343314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1890557224.

The product of its digits is 15552, while the sum is 30.

Adding to 11343343314 its reverse (41334334311), we get a palindrome (52677677625).

The spelling of 11343343314 in words is "eleven billion, three hundred forty-three million, three hundred forty-three thousand, three hundred fourteen".

Divisors: 1 2 3 6 1890557219 3781114438 5671671657 11343343314