Base | Representation |
---|---|
bin | 110100110100100110… |
… | …0010111101101100001 |
3 | 101211210102002021002121 |
4 | 1221221030113231201 |
5 | 3324303101001400 |
6 | 124035540144241 |
7 | 11124000043630 |
oct | 1515114275541 |
9 | 354712067077 |
10 | 113434000225 |
11 | 4411a599327 |
12 | 19b98998081 |
13 | a909a986c0 |
14 | 56c12c1517 |
15 | 2e3d81921a |
hex | 1a69317b61 |
113434000225 has 48 divisors (see below), whose sum is σ = 175556263680. Its totient is φ = 70788614400.
The previous prime is 113434000223. The next prime is 113434000231. The reversal of 113434000225 is 522000434311.
It is not a de Polignac number, because 113434000225 - 21 = 113434000223 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a self number, because there is not a number n which added to its sum of digits gives 113434000225.
It is not an unprimeable number, because it can be changed into a prime (113434000223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 189610 + ... + 512659.
It is an arithmetic number, because the mean of its divisors is an integer number (3657422160).
Almost surely, 2113434000225 is an apocalyptic number.
It is an amenable number.
113434000225 is a deficient number, since it is larger than the sum of its proper divisors (62122263455).
113434000225 is a wasteful number, since it uses less digits than its factorization.
113434000225 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 702370 (or 702365 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 113434000225 its reverse (522000434311), we get a palindrome (635434434536).
The spelling of 113434000225 in words is "one hundred thirteen billion, four hundred thirty-four million, two hundred twenty-five", and thus it is an aban number.
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